From 9131fb609bad03b75292e8959c3ad361b6537ae0 Mon Sep 17 00:00:00 2001
From: umsangdon <umsangdon@gmail.com>
Date: Thu, 12 Nov 2026 19:14:24 +0900
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822-2 새 식 여섯 · 목록 밖 기계(3450-0642)를 몰라 옮긴 기계를 손료만 식에 되넣으려 함 — 빌더만 고침(정본 · 기계표 그대로).

Co-Authored-By: Claude Sonnet 5.5 <noreply@anthropic.com>
---
 .../scripts/build_기계목록_빠진기계_814_1.py  | 26 ++++++++++++++++++-
 1 file changed, 25 insertions(+), 1 deletion(-)

diff --git a/resources/master_data/scripts/build_기계목록_빠진기계_814_1.py b/resources/master_data/scripts/build_기계목록_빠진기계_814_1.py
index f822bba99..df21a4cd5 100644
--- a/resources/master_data/scripts/build_기계목록_빠진기계_814_1.py
+++ b/resources/master_data/scripts/build_기계목록_빠진기계_814_1.py
@@ -53,8 +53,27 @@ def _has(row: dict, field: str) -> bool:
         return False
 
 
+NUMS = ("가격", *FIX, "손료계수", "주연료", "조종원", "잡재료율")
+
+
+def _bad(row: dict, field: str) -> bool:
+    v = (row.get("값") or {}).get(field)
+    if v in (None, ""):
+        return False
+    try:
+        float(str(v).replace(",", ""))
+    except ValueError:
+        return True
+    return False
+
+
 def family_of(row: dict) -> tuple[str | None, list[str]]:
     """기계표 한 줄 → (식 키 | None, 빈 값 이름들) — 연료 · 조종원 유무로 식 가족을 고름."""
+    bad = [
+        f for f in NUMS if _bad(row, f)
+    ]  # 수 아닌 글(「73.7+」 · 「13∼18」) = 풀지 않음(822-2 DROP_ONLY)
+    if bad:
+        return None, bad
     fuel, crew, job = _has(row, "주연료"), _has(row, "조종원"), _has(row, "조종원직종")
     if fuel and crew:
         key = "GC000268" if job else "GC000275"
@@ -75,12 +94,17 @@ def _rows() -> list[dict]:
     ]
 
 
+def _is_family(row: dict) -> bool:
+    """옛 식 묶음 + 「기계경비식」 부품 표지 전부(822-2 새 식 여섯 포함 — 옮긴 기계를 손료만 식에 되넣지 않음)."""
+    return row.get("키") in FAMILY or (row.get("부품") or {}).get("갈래") == "기계경비식"
+
+
 def _logic_lists(text: str) -> dict[str, list[str]]:
     data = json.loads(text)
     out = {}
     for row in data["줄"]:
         for i in row.get("입력") or []:
-            if row.get("키") in FAMILY and i.get("이름") == "기계":
+            if _is_family(row) and i.get("이름") == "기계":
                 out[row["키"]] = [str(c) for c in i.get("고르기") or []]
     return out