Aislo/resources/tester/test_642_1_clause_formula.py

"""785-1(642-1) 지킴 — 출처 풀이 · 조항 색인(`M02_Hopyo_Clause`) · 블록 글 → 절 나무 · 상수 ·
대입식 · 절 몫(`M02_Hopyo_Formula`) · 북부청 견본 엑셀(설계 642-A 5-3 첫 줄 기대).
읽기만 · 서버 없음.
"""

from __future__ import annotations

import sys
import warnings
from functools import lru_cache
from pathlib import Path

import pytest

ROOT = Path(__file__).resolve().parents[2]
if str(ROOT) not in sys.path:
    sys.path.insert(0, str(ROOT))

from M02_MasterTemplete import M02_Hopyo_Basis as basis  # noqa: E402
from M02_MasterTemplete import M02_Hopyo_Clause as clause  # noqa: E402
from M02_MasterTemplete import M02_Hopyo_Excel as hx  # noqa: E402
from M02_MasterTemplete import M02_Hopyo_Formula as fm  # noqa: E402

warnings.filterwarnings("ignore", category=UserWarning, module="openpyxl")
XLS = (
    ROOT
    / "resources/knowledge/original/실무문서/2026_실무일위대가 모음"
    / "2026년_북부지방산림청_임도사업_설계내역서(공통단가).xls"
)


@lru_cache(maxsize=1)
def blocks() -> dict[int, dict]:
    if not XLS.exists():
        pytest.skip("견본 엑셀 없음")
    book = hx.read_book(XLS.name, XLS.read_bytes())
    return {b["번"]: b for b in book["단산"]}


@lru_cache(maxsize=None)
def got(no: int) -> dict:
    return clause.basis(blocks()[no])


def keys(no: int) -> set[str]:
    return {o["키"] for o in got(no)["후보"]}


# ── 조항 색인 → 후보 ──────────────────────────────────────────────────
@pytest.mark.parametrize(
    "no, want",
    [
        (10, {"GC001140", "GC001141", "GC001142"}),
        (46, {"GC000198"}),
        (24, {"GC000211"}),
        (47, {"GC000206", "GC000207"}),
        (39, {"GF000224", "GF000225"}),
    ],
)
def test_후보(no, want):
    assert keys(no) == want
    assert got(no)["표지"] is None


def test_윗마디_절마다():
    """47 「6-2」 → 절 「1. 현장가공」 GC000206 · 「2. 조립」 GC000207 · 공장가공은 뺌."""
    by = {o["키"]: (o["맞음"], o["절"]) for o in got(47)["후보"]}
    assert by == {"GC000206": ("윗마디", "1"), "GC000207": ("윗마디", "2")}
    assert {o["키"] for o in got(47)["뺌"]} >= {"GC000208"}


@pytest.mark.parametrize("no, mark", [(33, "준용"), (6, "옛 번호"), (3, "번호 없음")])
def test_표지(no, mark):
    assert got(no)["표지"] == mark


def test_준용_결과단위_거름_절_번호():
    """33 「산림 12-12 준용」 → GF000177(원/식) 뺌 · 절 4 「표준품셈3-4-8」 → GC000110."""
    r = got(33)
    assert {o["키"]: o["까닭"][:7] for o in r["뺌"]} == {"GF000177": "결과단위 다름"}
    assert [(o["키"], o["절"]) for o in r["후보"]] == [("GC000110", "4")]


def test_색인_옛이름():
    assert set(clause.index()[("건설품셈 공통", "1-2-7")]) == {"GC001140", "GC001141", "GC001142"}
    assert clause.nature("원/10㎡") == "면적" and clause.nature("원/자재 단위") is None
    assert basis.settle is clause.settle and basis.no_basis is clause.no_basis


# ── 절 나무 ───────────────────────────────────────────────────────────
def _works(no: int) -> list[str]:
    nodes = blocks()[no]["절"]
    ids = {id(w) for w in fm.works(nodes)}
    return [p for p, one in clause._paths(nodes) if id(one) in ids]


def test_절_나무():
    assert _works(47) == ["1", "2"]
    assert _works(6) == ["1.가", "1.나", "1.다", "3"]
    assert [n["번"] for n in blocks()[6]["절"]] == ["1", "3", "4"]  # 「2.」 빠짐 그대로
    assert _works(24) == []  # 재료비 · 인건비 · 합계뿐 = 블록 통째
    b = blocks()[47]
    assert len(b["글행"]) == len(b["글"])
    one = fm.find(b["절"], "1")
    assert one["소계"] == {"노무비": 217540.1, "재료비": 19578.6, "경비": None, "계": 237118.7}
    lo, hi = b["행"]
    assert all(lo < r <= hi for r in one["행"])


# ── 상수 · 대입식 · 몫 ─────────────────────────────────────────────────
def _consts(no: int, path: str) -> dict[str, dict]:
    return {c["기호"]: c for c in fm.find(blocks()[no]["절"], path)["상수"]}


def test_상수():
    c = _consts(10, "1")
    assert (c["L"]["값"], c["L"]["단위"]) == (6, "m")
    assert (c["경사도"]["값"], c["경사도"]["단위"]) == (35, "°")
    assert (c["n"]["값"], c["n"]["이름"]) == (42, "운반회수")
    c = _consts(6, "1.나")
    assert {k: c[k]["값"] for k in ("q", "K", "f", "E", "Cm")} == {
        "q": 0.6,
        "K": 0.55,
        "f": 1,
        "E": 0.35,
        "Cm": 18,
    }
    assert (c["q"]["단위"], c["Cm"]["단위"], c["Cm"]["덧"]) == ("㎥", "sec", "90˚")
    assert isinstance(c["q"]["행"], int)


def test_대입식():
    p = next(f for f in fm.find(blocks()[10]["절"], "1")["식"] if f["기호"] == "P")
    assert p["꼴"] == "곱" and p["값"] == 0.547619
    assert [(f["수"], f["단위"]) for f in p["분자"]] == [
        (1, "㎡"),
        (575, "㎏/㎡"),
        (1, "회"),
        (1, "일"),
    ]
    assert p["분모"] == [{"수": 25, "단위": "㎏"}, {"기호": "n", "단위": ""}]
    assert p["대입"] == {"n": 42}


def test_절_몫():
    nodes = blocks()[6]["절"]
    share = fm.find(nodes, "1.나")["몫"]
    assert share["글"] == "× 575 / 1750 × 90%"
    assert share["값"] == pytest.approx(575 / 1750 * 0.9, abs=1e-6)
    assert fm.find(nodes, "1.가")["몫"]["값"] == 0.1
    assert fm.find(nodes, "3")["몫"]["값"] == pytest.approx(575 / 1750, abs=1e-6)
    assert fm.find(blocks()[47]["절"], "1")["몫"] is None


def test_인자_괄호():
    got_ = fm.factors("Cm × n / (60 × Es)")
    assert [(w, f.get("기호") or f.get("수")) for w, f in got_] == [
        ("곱", "Cm"),
        ("곱", "n"),
        ("나눔", 60),
        ("나눔", "Es"),
    ]
    assert fm.factors("t1 + t2") is None and fm.factors("1 2") is None