eomsangdonandClaude Opus 5.5
94838450d8
- 빈 캐시 폴더에서 table() 이 None 을 먼저 메모하면 build() 뒤에도 ready() 거짓 · 맞춤 「맞음」 0 이던 흠 - 시험: 캐시 쓰기 읽기 준비 전 none 에 build 직후 ready() 참 · table() = build 결과 한 줄 Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_01Ji4nuyLVHcxrXWHTdb5nRD
79 lines
3.1 KiB
Python
79 lines
3.1 KiB
Python
"""338-1 우리 로직 지문(`M02_Hopyo_Ours`) — 판 열쇠 · 캐시 쓰기 · 읽기 · 준비 전 None · 합판 품 ·
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기계경비 로직 · 섞기 전 변형 · 엔진 셈 캐시 · master_data 원본 그대로. 캐시 폴더는 임시."""
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import pytest
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from M02_MasterTemplete import M02_Hopyo_Fit as fit
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from M02_MasterTemplete import M02_Hopyo_Match as hm
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from M02_MasterTemplete import M02_Hopyo_Ours as ours
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from resources.tester.test_m02_hopyo_excel import master_hash
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approx = pytest.approx
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@pytest.fixture
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def cache(tmp_path, monkeypatch):
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"""임시 캐시 폴더 + 로직 셋만 셈(1,438 대신) — 끝나면 메모리 표를 비움."""
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monkeypatch.setenv("AISLO_HOPYO_CACHE", str(tmp_path))
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few = [x for x in hm.targets()["로직"] if x["로직"] in ("GC000211", "GC000198", "GC000268")]
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monkeypatch.setattr(hm, "targets", lambda: {**hm._targets(id(ours.whole())), "로직": few})
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monkeypatch.setitem(ours._STATE, "표판", None)
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monkeypatch.setitem(ours._STATE, "표", None)
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yield tmp_path
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ours._STATE.update(표판=None, 표=None)
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def test_판_열쇠_같음():
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a, b = ours.version(), ours.version()
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assert a == b and len(a) == 16 and ours.path_of(a).name == f"우리지문_{a}.json"
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def test_캐시_쓰기_읽기_준비_전_none(cache):
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before = master_hash()
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assert ours.table() is None and not ours.ready()
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built = ours.build()
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assert [o["로직"] for o in built] == ["GC000198", "GC000211", "GC000268"]
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assert ours.path_of().parent == cache and ours.path_of().is_file()
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assert ours.ready() and ours.table() == built
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ours._STATE.update(표판=None, 표=None)
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assert [o["로직"] for o in ours.table()] == ["GC000198", "GC000211", "GC000268"]
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assert master_hash() == before
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def test_데움_뒤_스레드(cache):
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thread = ours.warm(build_missing=True)
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thread.join(timeout=120)
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assert ours.ready() and len(ours.table()) == 3
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def test_합판_보통_형틀목공():
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fp = ours.fingerprint("GC000211", "㎡")
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plain = next(v for v in fp["변형"] if v["in"].get("유형") == "보통")
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assert plain["L"]["형틀목공"] == approx(0.112, abs=1e-3)
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assert plain["L"]["보통인부"] == approx(0.045, abs=1e-3)
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assert fp["직종"] == ["보통인부", "형틀목공"] and not fp["기계경비"]
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assert fp["고름조건"]["횟수"] # 고르기 글 「4회사용시」 낱말
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def test_기계경비_로직은_고른_기계_1시간():
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v = ours.run("GC000268", {})
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assert v["L"] == {} and len(v["X"]) == 1 and v["X"][0][2] == 1.0
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assert ours.fingerprint("GC000268", "hr")["기계경비"]
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def test_섞기_전_변형():
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table = ours.table() or ours.build()
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mixed = next(
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o
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for o in table
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if any(0 < ((v.get("mix") or {}).get("인력비율") or 0) < 100 for v in o["변형"])
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)
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prep = fit._prep(mixed, {})
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assert any(v["in"] and v["in"].get("_섞기전") for v in prep["vs"])
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def test_엔진_셈_캐시():
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a = ours.run("GC000198", {"소량감률": 50})
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assert ours.run("GC000198", {"소량감률": 50}) is a # 같은 입력은 다시 안 셈
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assert ours.run("없는로직", {}) is None
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